document.write( "Question 1187194: If we define x*y to mean 3x+2y, and x^y to mean 4x-y, then the value of (-2^3)*(3^-2) is\r
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document.write( "(A) -55 (B) -5 (C) 0 (D) 5 (E) 20 \n" );
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Algebra.Com's Answer #818144 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x^y = 4x-y \n" ); document.write( "(-2)^(3) = 4(-2)-3 \n" ); document.write( "(-2)^(3) = -8-3 \n" ); document.write( "(-2)^(3) = -11 \n" ); document.write( "Let A = (-2)^(3) = -11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^y = 4x-y \n" ); document.write( "(3)^(-2) = 4(3)-(-2) \n" ); document.write( "(3)^(-2) = 12+2 \n" ); document.write( "(3)^(-2) = 14 \n" ); document.write( "Let B = (3)^(-2) = 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x * y = 3x+2y \n" ); document.write( "A * B = 3A+2B \n" ); document.write( "A * B = 3(-11)+2(14) \n" ); document.write( "A * B = -33+28 \n" ); document.write( "A * B = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: (B) -5 \n" ); document.write( " \n" ); document.write( " |