document.write( "Question 1187189: After making a trip of (26 km, Christina found that if she had increased her average speed by 8 km
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document.write( "per hour. she could have made the trip in one hour less time. Find Christina's original rate.
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Algebra.Com's Answer #818141 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Each way of the trip would be 26 km. \n" ); document.write( "r, the original speed \n" ); document.write( "r+8, the not-done higher speed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time difference would have been 1 hour.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Simplify and solve.\r \n" ); document.write( "\n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Gen. Soln. Quadratic Eq. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |