document.write( "Question 111953: Question is not from the text.
\n" ); document.write( "Could you please tell me how to set up the following problem?
\n" ); document.write( "How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold?\r
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Algebra.Com's Answer #81813 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of pure gold needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure gold added (x) plus the amount of pure gold in the 1% alloy (0.01)*5 has to equal the amount of pure gold in the final mixture (5+x)*0.06. So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "x+0.01*5=0.06(5+x) get rid of parens and simplify\r
\n" ); document.write( "\n" ); document.write( "x+0.05=0.3+0.06x subtract 0.06x and also 0.05 from both sides\r
\n" ); document.write( "\n" ); document.write( "x-0.06x+0.05-0.05=0.3-0.05+0.06x-0.06x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.94x=0.25
\n" ); document.write( "x=0.266 oz\r
\n" ); document.write( "\n" ); document.write( "0.266+0.05=0.06(5.266)
\n" ); document.write( "0.316~~~0.316\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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