document.write( "Question 1187168: The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq. ft., find its base and height. \n" ); document.write( "
Algebra.Com's Answer #818088 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "The base of a parallelogram is twice its height. \n" ); document.write( "If the area of the parallelogram is 72 sq. ft., find its base and height. \n" ); document.write( "~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let the height be x; then the base is 2x.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The area equation is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " (2x)*x = 72 sq.ft\r\n" ); document.write( "\r\n" ); document.write( " 2x^2 = 72\r\n" ); document.write( "\r\n" ); document.write( " x^2 = 72/2 = 36\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |