document.write( "Question 1187160: A train is going at 1/4 of its usual speed and it take an extra 45 minutes to reach its destination. Find its usual time to cover the same distance. \n" ); document.write( "
Algebra.Com's Answer #818087 by ankor@dixie-net.com(22740)\"\" \"About 
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A train is going at 1/4 of its usual speed and it take an extra 45 minutes to reach its destination.
\n" ); document.write( " Find its usual time to cover the same distance.
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\n" ); document.write( "let s = the normal speed
\n" ); document.write( "then
\n" ); document.write( ".25s = the actual speed
\n" ); document.write( "and
\n" ); document.write( "t = normal time
\n" ); document.write( "Change 45 min = .75 hrs
\n" ); document.write( ":
\n" ); document.write( "write a distance equation, dist = speed*time
\n" ); document.write( "st = .25s(t +.75)
\n" ); document.write( "st = .25st + .1875s
\n" ); document.write( "simplify, divide by s
\n" ); document.write( "t = .25t + .1875
\n" ); document.write( "t - .25t = .1875
\n" ); document.write( ".75t = .1875
\n" ); document.write( "t = .1875/.75
\n" ); document.write( "t = .25 hrs or 15 min is the normal time
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