document.write( "Question 1187121: Given that S=7a+b+7c and also S=6a+8b+6c, where 51\n" );
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Algebra.Com's Answer #818066 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subtract [2] from [1]: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute [3] in [1]: \n" ); document.write( " \n" ); document.write( "We know a, b, and c are integers, so S is an integer. From the last equation, we also know that S is a multiple of 50, and (a+c) is a multiple of 7. \n" ); document.write( "We also know that S is between 51 and 149. The only multiple of 50 between 51 and 149 is 100. So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute [4] in [3]: \n" ); document.write( " \n" ); document.write( "Combine [4] and [5] to get the answer. \n" ); document.write( "ANSWER: a+b+c = 14+2 = 16 -- answer choice C \n" ); document.write( " \n" ); document.write( " |