document.write( "Question 1187084: What is the equation of the circle with center at(0.2) and tangent to the line
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document.write( "3x-4y=12
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Algebra.Com's Answer #818030 by Alan3354(69443) You can put this solution on YOUR website! What is the equation of the circle with center at(0.2) and tangent to the line \n" ); document.write( "3x-4y=12 \n" ); document.write( "---------------- \n" ); document.write( "There's a formula for the distance from a point to a line, but I'll work it the \"long way.\" \n" ); document.write( "--------- \n" ); document.write( "3x-4y=12 ---> y = (3/4)x - 3 \n" ); document.write( "Slope of the line is 3/4 \n" ); document.write( "Slope of lines perpendicular is -4/3 \n" ); document.write( "(0,2) is the y intercept ---> y = (-4/3)x + 2 \n" ); document.write( "Find the intersection of the 2 lines. \n" ); document.write( "--- \n" ); document.write( "y = (3/4)x - 3 \n" ); document.write( "y = (-4/3)x + 2 \n" ); document.write( "--- \n" ); document.write( "(3/4)x - 3 = (-4/3)x + 2 \n" ); document.write( "9x - 36 = -16x + 24 \n" ); document.write( "25x = 60 \n" ); document.write( "x = 2.4 \n" ); document.write( "y = -1.2 \n" ); document.write( "Intersection at (2.4,-1.2) \n" ); document.write( "Distance from (0,2) = sqrt(diffy^2 + diffx^2) = sqrt(2.4^2 + 3.2^2) = sqrt(16) = 4 \n" ); document.write( "------- \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |