document.write( "Question 1186933: -x < x
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Algebra.Com's Answer #817886 by Edwin McCravy(20060)\"\" \"About 
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document.write( "-x < x \r\n" );
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document.write( "find a counterexample.\r\n" );
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document.write( "x = 0 is a counterexample because -0 < 0 is the same as 0 < 0 which says something\r\n" );
document.write( "can be less than itself, which is false, so 0 is, in fact, the largest possible\r\n" );
document.write( "counterexample.\r\n" );
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document.write( "-x < x\r\n" );
document.write( "-0 < 0\r\n" );
document.write( " 0 < 0     <--nothing can be less that itself!\r\n" );
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document.write( "x = -1 is a counterexample because -(-1) is the same as 1, which also says something \r\n" );
document.write( "can be less than itself.\r\n" );
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document.write( "   -x < x\r\n" );
document.write( "-(-1) < 1\r\n" );
document.write( "    1 < 1   <--nothing can be less than itself. \r\n" );
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document.write( "-x < x is always true for positive numbers and is always false for zero and\r\n" );
document.write( "negative numbers.\r\n" );
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document.write( "Edwin
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