document.write( "Question 1186917: Find the sum of the series 4 + 12 + 36 + ….. + 8748. \n" ); document.write( "
Algebra.Com's Answer #817876 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We know the first term is \"4\", so
\n" ); document.write( "\"a%5B1%5D=4\"\r
\n" ); document.write( "\n" ); document.write( "Each term is \"3\" times bigger than the last, meaning we have \"a%5B1%5Dr%5E%28n-1%29\", with \"r=3\" \r
\n" ); document.write( "\n" ); document.write( "So, we know the series follows \"4%283%29%5E%28n-1%29\".\r
\n" ); document.write( "\n" ); document.write( "Foe a geometric series:\r
\n" ); document.write( "\n" ); document.write( "\"S%5Bn%5D=a%5B1%5D%28%281-r%5En%29%2F%281-r%29%29\"\r
\n" ); document.write( "\n" ); document.write( "we have: \"a%5B1%5D=4\" and \"r=3\" \r
\n" ); document.write( "\n" ); document.write( "We need \"n\" for the last term:\r
\n" ); document.write( "\n" ); document.write( "\"4%283%29%5E%28n-1%29=8748\"\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%28n-1%29=2187\".......since \"2187=3%5E7\"\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%28n-1%29=3%5E7\"........since bases same, equal the exponents\r
\n" ); document.write( "\n" ); document.write( "\"n-1=7\"\r
\n" ); document.write( "\n" ); document.write( "\"n=8\"\r
\n" ); document.write( "\n" ); document.write( "\"S%5B8%5D=4%28%281-3%5E8%29%2F%281-3%29%29\"
\n" ); document.write( "\"S%5B8%5D=4%28%28-6560%29%2F%28-2%29%29\"
\n" ); document.write( "\"S%5B8%5D=4%283280%29\"
\n" ); document.write( "\"S%5B8%5D=13120\"\r
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