document.write( "Question 1186882: center at the origin; a focus (0,2); vertex at (0,3) \n" ); document.write( "
Algebra.Com's Answer #817850 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "center at the origin; a focus (0,2); vertex at (0,3)
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document.write( "The focus is closer to the center than the vertex ---> hence, the conic section is an ellipse.\r\n" );
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document.write( "A focus and a vertex lie on vertical line x= 0  ---> hence, the major axis is vertical.\r\n" );
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document.write( "The length of the major semi-axis is a = 3.\r\n" );
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document.write( "We find the length of the minor semi-axis b from the equation\r\n" );
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document.write( "    b = \"sqrt%28a%5E2+-+c%5E2%29\",  where c is the eccentriciry  c= 2 (given).\r\n" );
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document.write( "So,  b = \"sqrt%283%5E2+-+2%5E2%29\" = \"sqrt%289-4%29\" = \"sqrt%285%29\".\r\n" );
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document.write( "Thus the equation of the ellipse is\r\n" );
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document.write( "    \"x%5E2%2F5\" + \"y%5E2%2F9\" = 1.\r\n" );
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