document.write( "Question 1186872: Three consecutive terms of a geometric progression are x,x+6 and x+9.Find the value of x. \n" ); document.write( "

Algebra.Com's Answer #817845 by ikleyn(52810) $\"\"$ $\"About$

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\n" ); document.write( "Three consecutive terms of a geometric progression are x,x+6 and x+9.Find the value of x.
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document.write( "Since the three terms are consecutive terms of a GP, we have this equation\r\n" );
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document.write( "     = .\r\n" );
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document.write( "To solve, cross multiply; then simplify\r\n" );
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document.write( "    x*(x+9) = \r\n" );
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document.write( "    x^2 + 9x = x^2 + 12x + 36\r\n" );
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document.write( "          9x =       12x + 36\r\n" );
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document.write( "          9x - 12x = 36\r\n" );
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document.write( "            -3x    = 36\r\n" );
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document.write( "              x    =  = -12.\r\n" );
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document.write( "The terms are  -12,  -12+6 = -6,  -12 + 9 = -3.\r\n" );
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document.write( "ANSWER.  The terms are  -12, -6, -3.\r\n" );
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