document.write( "Question 112057: I have to solve the equation by factoring first and then applying the zero product principle. so, can someone help me solve x^3 +x^2-7x=7. any help would be appreciated. \n" ); document.write( "
Algebra.Com's Answer #81781 by Earlsdon(6294)\"\" \"About 
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Factor:
\n" ); document.write( "\"x%5E3%2Bx%5E2-7x+=+7\" Subtract 7 from both sides.
\n" ); document.write( "\"x%5E3%2Bx%5E2-7x-7=+0\" Factor by grouping.
\n" ); document.write( "\"%28x%5E3%2Bx%5E2%29+-+%287x%2B7%29+=+0\" Factor \"x%5E2\" from the first group and 7 from the second group.
\n" ); document.write( "\"x%5E2%28x%2B1%29+-+7%28x%2B1%29=+0\" Now factor the common factor of \"%28x%2B1%29\"
\n" ); document.write( "\"%28x%2B1%29%28x%5E2-7%29+=+0\" Now apply the zero products principle.
\n" ); document.write( "\"x%2B1+=+0\" or \"x%5E2-7+=+0\"
\n" ); document.write( "If \"x%2B1+=+0\" then \"x+=+-1\"
\n" ); document.write( "if \"x%5E2-7+=+0\" then \"x%5E2+=+7\" so \"x+=+sqrt%287%29\" or \"x+=+-sqrt%287%29\"
\n" ); document.write( "The three roots are:
\n" ); document.write( "\"x+=+-1\"
\n" ); document.write( "\"x+=+sqrt%287%29\"
\n" ); document.write( "\"x+=+-sqrt%287%29\"
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