document.write( "Question 1186817: write a rational function f with the following properties.\r
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document.write( "f has a vertical asymptote x=2, hole at x=-6, x-intercept (1,0), and end behavior model q(x)=x+7 \n" );
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Algebra.Com's Answer #817790 by greenestamps(13215) You can put this solution on YOUR website! \n" ); document.write( "(1) vertical asymptote at x=2: there is a factor of (x-2) in the denominator but not in the numerator \n" ); document.write( "(2) hole at x=-6: there are factors of (x+6) in both numerator and denominator \n" ); document.write( "(3) x-intercept (1,0): there is a factor of (x-1) in the numerator but not in the denominator \n" ); document.write( "At this point, the parts of the function we have are these: \n" ); document.write( " \n" ); document.write( "That function has a horizontal asymptote at y=1; we need a slant asymptote of y=x+7. To get a slant asymptote, we need an additional factor (x-a) in the numerator such that \n" ); document.write( " \n" ); document.write( "has quotient (x+7) (and we don't care about the remainder) \n" ); document.write( "We can determine the constant a using synthetic division of (x-1)(x-a) = x^2+(-a-1)x+a by x-2: \r\n" ); document.write( "\r\n" ); document.write( " 2 | 1 -a-1 a\r\n" ); document.write( " | 2 ...\r\n" ); document.write( " +---------------\r\n" ); document.write( " 1 -a+1 ... \n" ); document.write( "Since we want the asymptote to be y=x+7, we need to have \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The additional factor we need in the numerator is (x-(-6)) = (x+6). \n" ); document.write( "ANSWER: \n" ); document.write( "A graph, showing the slant asymptote... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |