document.write( "Question 112073: Hello out there,I really need some help with some tough problems,the first one is,Find the distance between the two points given.Round to the nearest tenth,if necessary,(1,1)and(3,2).The next one is,Find the distance between the two points given.Round to the nearest tenth,if necessary,(4,0)and(6,3).The third one is Find the distance between the two points given.Round to the nearest tenth,if necessary,(5,2)and(5,-2).And the last one is,Find the distance between the two points given.Round to the nearest tenth,if necessary,(1,3)and(1,5).Thanks to whoever can help. \n" ); document.write( "
Algebra.Com's Answer #81774 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
#1\r
\n" ); document.write( "\n" ); document.write( "Start with the given distance formula\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" where is the first point and is the second point \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%281-3%29%5E2%2B%281-2%29%5E2%29\" Plug in \"x%5B1%5D=1\", \"x%5B2%5D=3\", \"y%5B1%5D=1\", \"y%5B2%5D=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-2%29%5E2%2B%28-1%29%5E2%29\" Evaluate \"1-3\" to get -2. Evaluate \"1-2\" to get -1. \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%284%2B1%29\" Square each value\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%285%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the distance approximates to\r
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\n" ); document.write( "\n" ); document.write( "\"d=2.23606797749979\"\r
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\n" ); document.write( "\n" ); document.write( "which rounds to\r
\n" ); document.write( "\n" ); document.write( "2.2\r
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\n" ); document.write( "\n" ); document.write( "So the distance between (1,1) and (3,2) is approximately 2.2 units\r
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\n" ); document.write( "\n" ); document.write( "#2\r
\n" ); document.write( "\n" ); document.write( "Start with the given distance formula\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" where is the first point and is the second point \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%284-6%29%5E2%2B%280-3%29%5E2%29\" Plug in \"x%5B1%5D=4\", \"x%5B2%5D=6\", \"y%5B1%5D=0\", \"y%5B2%5D=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-2%29%5E2%2B%28-3%29%5E2%29\" Evaluate \"4-6\" to get -2. Evaluate \"0-3\" to get -3. \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%284%2B9%29\" Square each value\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2813%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the distance approximates to\r
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\n" ); document.write( "\n" ); document.write( "\"d=3.60555127546399\"\r
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\n" ); document.write( "\n" ); document.write( "which rounds to\r
\n" ); document.write( "\n" ); document.write( "3.6\r
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\n" ); document.write( "\n" ); document.write( "So the distance between (4,0) and (6,3) is approximately 3.6 units\r
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\n" ); document.write( "\n" ); document.write( "#3\r
\n" ); document.write( "\n" ); document.write( "Start with the given distance formula\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" where is the first point and is the second point \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%285-5%29%5E2%2B%282--2%29%5E2%29\" Plug in \"x%5B1%5D=5\", \"x%5B2%5D=5\", \"y%5B1%5D=2\", \"y%5B2%5D=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%280%29%5E2%2B%284%29%5E2%29\" Evaluate \"5-5\" to get 0. Evaluate \"2--2\" to get 4. \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%280%2B16%29\" Square each value\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2816%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"d=4\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "So the distance between (5,2) and (5,-2) is 4 units\r
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\n" ); document.write( "\n" ); document.write( "#4\r
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\n" ); document.write( "\n" ); document.write( "Start with the given distance formula\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" where is the first point and is the second point \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%281-1%29%5E2%2B%283-5%29%5E2%29\" Plug in \"x%5B1%5D=1\", \"x%5B2%5D=1\", \"y%5B1%5D=3\", \"y%5B2%5D=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%280%29%5E2%2B%28-2%29%5E2%29\" Evaluate \"1-1\" to get 0. Evaluate \"3-5\" to get -2. \r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%280%2B4%29\" Square each value\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%284%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"d=2\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "So the distance between (1,3) and (1,5) is 2 units
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