document.write( "Question 1186705: A rectangle was formed from a piece of wire whose length is 4m more than its
\n" ); document.write( "width. The wire is bent again into a semi-circle with radius 17m, find the area of the
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Algebra.Com's Answer #817665 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Dimensions of rectangle
\n" ); document.write( "w+4 and w
\n" ); document.write( "Perimeter is \"2%28w%2B4%29%2B2w=4w%2B4\".\r
\n" ); document.write( "\n" ); document.write( "Rectangle's area is \"w%5E2%2B4w\".\r
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\n" ); document.write( "\n" ); document.write( "Semi-circle, radius 17 meters
\n" ); document.write( "Area is \"%281%2F2%29pi%2A17%5E2=%28289%2F2%29pi\"\r
\n" ); document.write( "\n" ); document.write( "Perimeter is \"%281%2F2%292pi%2A17%2B34=17pi%2B34\"\r
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\n" ); document.write( "\n" ); document.write( "The two perimeters are equal in length.
\n" ); document.write( "\"4w%2B4=17pi%2B34\"
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\n" ); document.write( "\"4w=17pi%2B30\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28w=%2817pi%2B30%29%2F4%29\"---------width\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28w%2B4=%2817pi%2B30%29%2F4%2B4%29\"---------length\r
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\n" ); document.write( "\n" ); document.write( "You can multiply to get the area and simplify, or compute the value.
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