document.write( "Question 1186693: Find the sum of the series 15/42+15/56+15/72+15/90+…+15/9900 \n" ); document.write( "
Algebra.Com's Answer #817641 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Find the sum of the series 15/42+15/56+15/72+15/90+…+15/9900
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document.write( "The series is 15 times  S = \"1%2F42+%2B+1%2F56+%2B+1%2F72+%2B+1%2F90+%2B+ellipsis+%2B+1%2F9900\"\r\n" );
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document.write( "Each addend in the sum S is\r\n" );
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document.write( "    \"1%2F42\" = \"1%2F6+-+1%2F7\"         (1)\r\n" );
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document.write( "    \"1%2F56\" = \"1%2F7+-+1%2F8\"       \r\n" );
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document.write( "    \"1%2F72\" = \"1%2F8+-+1%2F9\"\r\n" );
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document.write( "    \"1%2F90\" = \"1%2F9+-+1%2F10\"\r\n" );
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document.write( "       . . . and so on . . . \r\n" );
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document.write( "    \"1%2F9900\" = \"1%2F99+-+1%2F100\"     (last)\r\n" );
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document.write( "The pattern is clear.\r\n" );
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document.write( "When you add the lines from (1) to the (last),  all  intermediate terms with opposite signs will cancel each other, \r\n" );
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document.write( "leaving only  \"1%2F6+-+1%2F100\" = \"%28100-6%29%2F600\" = \"94%2F600\".\r\n" );
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document.write( "So the ANSWER to the problem's question is  \"15%2A%2894%2F600%29\" = \"94%2F40\" = \"47%2F20\" = 2.35.\r\n" );
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