document.write( "Question 1186641: a picture frame on colored cardboard 40 cm by 32cm. if there is a uniform border around the picture such that area of the border is 720 cm2.find the length and width of the picture. \n" ); document.write( "
Algebra.Com's Answer #817585 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The cardboard is 8cm longer than it is wide. Since the border is uniform, the picture itself is 8cm longer than it is wide. \n" ); document.write( "The area of the cardboard is 40*32=1280 cm^2; the area of the border is 720 cm^2. So the area of the picture is 1280-720=560 cm^2. \n" ); document.write( "Let x be the width of the picture; then x+8 is the length. Since the area is 560... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=-28 or x=20 \n" ); document.write( "Obviously the negative answer makes no sense in the problem. So x=20. \n" ); document.write( "ANSWER: \n" ); document.write( "picture width: x=20cm \n" ); document.write( "picture length: x+8=28cm \n" ); document.write( "Note in solving the problem using formal algebra we had to factor a quadratic expression by finding two numbers whose difference is 8 and whose product is 560. That's what the original problem required us to do; so the formal algebra didn't get us any closer to the answer. \n" ); document.write( "Trial and error and a bit of mental arithmetic will get us to the solution quickly: \n" ); document.write( "560=56*10 no... \n" ); document.write( "560=14*40 no... \n" ); document.write( "560=28*20 YES! \n" ); document.write( " \n" ); document.write( " |