document.write( "Question 1186641: a picture frame on colored cardboard 40 cm by 32cm. if there is a uniform border around the picture such that area of the border is 720 cm2.find the length and width of the picture. \n" ); document.write( "
Algebra.Com's Answer #817585 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The cardboard is 8cm longer than it is wide. Since the border is uniform, the picture itself is 8cm longer than it is wide.

\n" ); document.write( "The area of the cardboard is 40*32=1280 cm^2; the area of the border is 720 cm^2. So the area of the picture is 1280-720=560 cm^2.

\n" ); document.write( "Let x be the width of the picture; then x+8 is the length. Since the area is 560...

\n" ); document.write( "\"x%28x%2B8%29=560\"
\n" ); document.write( "\"x%5E2%2B8x=560\"
\n" ); document.write( "\"x%5E2%2B8x-560=0\"
\n" ); document.write( "\"%28x%2B28%29%28x-20%29=0\"

\n" ); document.write( "x=-28 or x=20

\n" ); document.write( "Obviously the negative answer makes no sense in the problem. So x=20.

\n" ); document.write( "ANSWER:
\n" ); document.write( "picture width: x=20cm
\n" ); document.write( "picture length: x+8=28cm

\n" ); document.write( "Note in solving the problem using formal algebra we had to factor a quadratic expression by finding two numbers whose difference is 8 and whose product is 560. That's what the original problem required us to do; so the formal algebra didn't get us any closer to the answer.

\n" ); document.write( "Trial and error and a bit of mental arithmetic will get us to the solution quickly:
\n" ); document.write( "560=56*10 no...
\n" ); document.write( "560=14*40 no...
\n" ); document.write( "560=28*20 YES!

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