document.write( "Question 1186589: Determine the probabilities of having
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Algebra.Com's Answer #817536 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "(a)  With 4 children in a family, there are, in total,  = 16 possible different configurations of boys/girls.\r\n" );
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document.write( "     Of them, there is only one \"unfavorable\" configuration, when all the children are boys.\r\n" );
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document.write( "     All other 15 configurations have at least one girl.\r\n" );
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document.write( "     So, there are 16 total configurations and of them, there are 15 favorable, having at least one girl.\r\n" );
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document.write( "     THEREFORE, the probability to have at least one girl in a family with 4 children \r\n" );
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document.write( "                is  .          ANSWER\r\n" );
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document.write( "(b)  Again, there are 16 possible different configurations, in all.\r\n" );
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document.write( "     Of them, \"unfavorable\" are only 2 (two), having all 4 boys  OR  having all 4 girls.\r\n" );
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document.write( "     The rest 16-2 = 14 configurations are \"favorable\" : they have at least one boy and at least one girl.\r\n" );
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document.write( "     \r\n" );
document.write( "     THEREFORE, the probability to have at least one girl AND at least one boy in a family with 4 children \r\n" );
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document.write( "                is   = .      ANSWER\r\n" );
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