document.write( "Question 1186176: Mrs Thomas baked 3 types of cookies for sale.
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document.write( "She baked 24 more walnut cookies than cashew nut cookies.
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document.write( "She baked 48 more cashew nut cookies than almond cookies\r
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document.write( "Mrs Thomas then sold 2/3 of the walnut cookies, 3/4 of the cashew nut cookies and
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document.write( "1/2 of the almond cookies. She had 140 cookies left at the end of the sale.
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document.write( "How many walnut cookies did Mrs Thomas bake? \n" );
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Algebra.Com's Answer #817524 by Octo-pie7(11)![]() ![]() You can put this solution on YOUR website! Let number of almond cookies = x \n" ); document.write( "then cashew nut cookies = (x + 48) \n" ); document.write( "walnut cookies = (x + 72) \n" ); document.write( "Total number of cookies = x + x + 48 + x + 72 = 3x + 120 \n" ); document.write( "Again walnut cookies sold = 2/3(x + 72) \n" ); document.write( "cashew nut cookies sold = 3/4(x + 48) \n" ); document.write( "almond cookies sold = x/2 \n" ); document.write( "Total cookies sold = x/2 + 2/3(x + 72) + 3/4(x + 48) = x/2 + 2x/3 + 48 + 3x/4 + 36 = 23x/12 + 84 \n" ); document.write( "Now as per question, \n" ); document.write( "3x + 120 - (23x/12 + 84) = 140 \n" ); document.write( "or, 3x - 23x/12 + 120 - 84 = 140 \n" ); document.write( "or, 13x/12 = 140 - 36 = 104 \n" ); document.write( "or, x = 104 × 12/13 = 96 \n" ); document.write( "Number of walnut cookies Mrs Thomas baked=96+72=168 \n" ); document.write( " |