document.write( "Question 1186567: The sixth and 13th terms of a geometric progression are 5/2 and 320 respectively.Find the common ratio,the first term and the 10th term of this progression. \n" ); document.write( "

Algebra.Com's Answer #817492 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "6th term: $\"ar%5E5=5%2F2\"$

\n" ); document.write( "13th term: $\"ar%5E12=320\"$

\n" ); document.write( "The standard method for solving a problem like this, given two terms of a geometric sequence: Divide the second equation by the first

\n" ); document.write( " $\"ar%5E12%2Far%5E5=320%2F%285%2F2%29\"$
\n" ); document.write( " $\"r%5E7=128\"$
\n" ); document.write( " $\"r=2\"$

\n" ); document.write( "1st term: 6th term, divided by r^5
\n" ); document.write( " $\"%285%2F2%29%2F%282%5E5%29=5%2F64\"$

\n" ); document.write( "10th term: 13th term, divided by r^3
\n" ); document.write( " $\"320%2F%282%5E3%29=40\"$

\n" ); document.write( "ANSWERS:
\n" ); document.write( "1st term 5/64
\n" ); document.write( "10th term 40

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