document.write( "Question 112042: Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. \n" ); document.write( "
Algebra.Com's Answer #81737 by BrittanyM(80) ![]() You can put this solution on YOUR website! We can use a system of equations in order to solve for the variables. \n" ); document.write( "Sally bought three chocolates and one pack of gum for 1.75 \n" ); document.write( "So: \n" ); document.write( "3C + 1G = 1.75 \n" ); document.write( "And Jake bought two chocolates and four packs of gum for 2.00 \n" ); document.write( "So: \n" ); document.write( "2C + 4G = 2.00\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3C + 1G = 1.75 \n" ); document.write( "2C + 4G = 2.00\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the top equation, we can subtract 3C in order to find the value of 1G in terms of C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1G = -3C + 1.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, we can plug this into the other equation to find the exat value of C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2C + 4(-3C + 1.75) = 2.00 \n" ); document.write( "2C - 12C + 7 = 2.00 \n" ); document.write( "-10C = -5 \n" ); document.write( "C = 0.50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we can plug this value into either of the equations from the system so we can solve for G.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3(0.50) + 1G = 1.75 \n" ); document.write( "1.5 + 1G = 1.75 \n" ); document.write( "1G = 0.25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So one chocolate costs 0.50, \n" ); document.write( "And one pack of gun costs 0.25. \n" ); document.write( " |