document.write( "Question 1186459: How much coffee costing P40 per kilo must be added to 150 kilos costing P48 per kilo to make a mixture costing P45 per kilo? \n" ); document.write( "
Algebra.Com's Answer #817367 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "How much coffee costing P40 per kilo must be added to 150 kilos costing P48 per kilo to make a mixture costing P45 per kilo? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "x = kilograms to add.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Money equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 40*x + 48*150 = 45*(150+x)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 40x + 48*150 = 45*150 + 45x\r\n" ); document.write( "\r\n" ); document.write( " 48*150 - 45*150 = 45x - 40x\r\n" ); document.write( "\r\n" ); document.write( " (48 - 45)*150 = 5x\r\n" ); document.write( "\r\n" ); document.write( " 3*150 = 5x\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |