document.write( "Question 1186342: At exactly 12 o’clock noon the hour hand of a clock begins to move at twice its
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document.write( "normal speed, and the minute hand begins to move backward at half its normal
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document.write( "speed. When the two hands next coincide, what will be the correct time? \n" );
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Algebra.Com's Answer #817312 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! At exactly 12 o’clock noon the hour hand of a clock begins to move at twice its \n" ); document.write( "normal speed, and the minute hand begins to move backward at half its normal \n" ); document.write( "speed. When the two hands next coincide, what will be the correct time? \n" ); document.write( " \r\n" ); document.write( "A normal hour hand moves 360 degrees in 12 hours or 30 degrees per hour.\r\n" ); document.write( "A normal minute hand moves 360 degrees per hour.\r\n" ); document.write( "\r\n" ); document.write( "On this abnormal clock, beginning at noon, the hour hand moves clockwise at 60\r\n" ); document.write( "degree per hour. \r\n" ); document.write( "\r\n" ); document.write( "On this abnormal clock, beginning at noon, the minute hand moves counter-\r\n" ); document.write( "clockwise at 180 degrees per hour.\r\n" ); document.write( "\r\n" ); document.write( "At noon the hands are together and can be considered to be either 0 degrees or\r\n" ); document.write( "360 degrees apart. At noon, the angle between the hands begins decreasing from\r\n" ); document.write( "360 degrees at the rate of the sum of their speeds (because the hands are\r\n" ); document.write( "approaching each other), which is 180+60=240 degrees per hour. The angle between\r\n" ); document.write( "them will decrease from 360 degrees to 0 degrees in 360/240 = 1.5 hours, which\r\n" ); document.write( "will be at 1:30 PM.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |