document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186381>Question 1186381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with the homework\r<BR>\n" );
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document.write( "At what period will 2500 double if interest is calculated half yearly at 11% interest per annum.\r<BR>\n" );
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document.write( "Thanks in advance<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817277 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At what period will 2500 double if interest is calculated half yearly at 11% interest per annum.<BR>\n" );
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document.write( "11%/year = 5.5% per period<BR>\n" );
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document.write( "5000 = 2500*(1 + 0.055)^t --- t in periods<BR>\n" );
document.write( "1.055^t = 2<BR>\n" );
document.write( "t*ln(1.055) = ln(2)<BR>\n" );
document.write( "t = ln(2)/ln(1.055)<BR>\n" );
document.write( "t = ~ 12.946 periods = 6.47 years </SPAN>\n" );
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