document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186330>Question 1186330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998).  Blood pressure is normally distributed.<BR>\n" );
document.write( "a.)	State the random variable.<BR>\n" );
document.write( "b.)	Suppose a sample of size 15 is taken.  State the shape of the distribution of the sample mean.<BR>\n" );
document.write( "c.)	Suppose a sample of size 15 is taken.  State the mean of the sample mean.<BR>\n" );
document.write( "d.)	Suppose a sample of size 15 is taken.  State the standard deviation of the sample mean.<BR>\n" );
document.write( "e.)	Suppose a sample of size 15 is taken.  Find the probability that the sample mean blood pressure is more than 135 mmHg.<BR>\n" );
document.write( "f.)	Would it be unusual to find a sample mean of 15 people in China of more than 135 mmHg?  Why or why not?<BR>\n" );
document.write( "g.)	If you did find a sample mean for 15 people in China to be more than 135 mmHg, what might you conclude?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817233 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> random variable is the blood pressure.<BR>\n" );
document.write( "n=15 from a normal distribution is normally distributed itself with sample mean (for n=15) 128, same as pop. mean and sd of 23/sqrt(15) mm<BR>\n" );
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document.write( "z=(xbar-mean)/sigma/sqrt(n)<BR>\n" );
document.write( "=(135-128)*sqrt(135)/23<BR>\n" );
document.write( "=1.18<BR>\n" );
document.write( "probability of that z or greater is 0.1190<BR>\n" );
document.write( "It would not be common but not unusual to find that value.<BR>\n" );
document.write( "If I found a value >135, what I would think of it would depend upon what my cutoff value for abnormal were, before I did the study. Since most cutoff values are <0.10, I would likely not consider the value abnormal. </SPAN>\n" );
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