document.write( "Question 111994: Hello, I am working on a word problem that I need some assistance on.
\n" ); document.write( "Here it is: A bus leaves a station at 1pm, traveling west at an average rate of 44m/h. One hour later a second bus leaves the same station at, traveling east at a rate of 48m/h. At what time will the two buses be 274 miles apart?\r
\n" ); document.write( "\n" ); document.write( "Now what I have been trying to do is take the rate of 44m/h and 48m/h and divide that into 274. I have come close to 7pm for the time at which the two buses will be 274 mi. apart. Is this the correct way of solving this problem or am I off base here? I appreciate your help here.\r
\n" ); document.write( "\n" ); document.write( "Thank You, Barb Neely
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Algebra.Com's Answer #81722 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A bus leaves a station at 1pm, traveling west at an average rate of 44m/h. One hour later a second bus leaves the same station at, traveling east at a rate of 48m/h. At what time will the two buses be 274 miles apart?
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\n" ); document.write( "The best way to do this is just write an equation that adds the two distances to equal 274 mi:
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\n" ); document.write( "Let t = travel time (in hrs) of the 1st bus to be 274 mi from the 2nd bus
\n" ); document.write( "Then
\n" ); document.write( "(t-1) = travel time of the 2nd bus to reach that 274 mi point
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\n" ); document.write( "Distance = speed * time
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\n" ); document.write( "2nd bus dist + 1st bus dist = 274
\n" ); document.write( "48(t-1) + 44t = 274
\n" ); document.write( "48t - 48 + 44t = 274
\n" ); document.write( "48t + 44t = 274 + 48
\n" ); document.write( "92t = 322
\n" ); document.write( "t = 322/92
\n" ); document.write( "t = 3.5 hrs
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\n" ); document.write( "3.5 hrs after 1 pm = 4:30 the time they're 274 mi apart
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\n" ); document.write( "WE can check this, the 2nd bus is traveling for only 2.5 hrs
\n" ); document.write( "48*2.5 = 120 mi from the starting point at 4:30 (leaves at 2pm)
\n" ); document.write( "44*3.5 = 154 mi from the starting point at 4:30 (left at 1 pm)
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\n" ); document.write( "total mi:274 mi
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\n" ); document.write( "Did this make sense to you?\r
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