document.write( "Question 1186190: The amounts of electricity bills for all households in a particular city have an
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document.write( "approximately normal distribution with a mean of $140 and a standard deviation of
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document.write( "$30. Find the probability that the mean amount of electricity bills for a random sample
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document.write( "of 75 households selected from this city will be between $132 and $136. My email address is www.cosmashiltoon@gmail.com
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Algebra.Com's Answer #817214 by Theo(13342)![]() ![]() You can put this solution on YOUR website! population mean = 140. \n" ); document.write( "population standard deviation = 30 \n" ); document.write( "sample size = 75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when you are dealing with the mean of a sample, you need to use the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard error = standard deviation divided by square root of smaple size = 30 / sqrt(75) = 3.4641 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that the sample mean will be between 132 and 136 is is equal to .1136 = 11.36%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "calculator used can be found at https://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of the results from using that calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |