document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186305>Question 1186305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are 7 letters which is U,N,I,F,O,R,M. Find the number of different four-letter codes which end with consonant (not repetition) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817209 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The only restriction (other than no repetition) is that the last letter in the 3-letter code must be a consonant.  So pick that letter first; there are 4 choices.<br><BR>\n" );
document.write( "Then pick the other three letters of the code (in any order).  There are 6 choices for the second letter you choose, 5 for the third, and 4 for the last.<br><BR>\n" );
document.write( "By the fundamental counting principle, the number of 4-letter codes with no repetition of letters and the last letter a consonant is 4*6*5*4 = 480.<br><BR>\n" );
document.write( "ANSWER: 480<br><BR>\n" );
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