document.write( "Question 1186316: Hi I need your help I'm struggling with solving this. Find the equation of the hyperbola, given vertices: (15,1), (-1,1); Endpoints of the conjugate axis: (7,7), (7,-5) \n" ); document.write( "

Algebra.Com's Answer #817208 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Previously solved....

\n" ); document.write( "The vertices are the endpoints of the transverse axis; the transverse axis is horizontal, so the branches of the hyperbola open left and right.

\n" ); document.write( "The general form of the equation of a hyperbola with center (h,k) and branches opening left and right is

\n" ); document.write( " $\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"$

\n" ); document.write( "To find the equation from the given information, you need to determine the center (h,k) and the values of a^2 and b^2.

\n" ); document.write( "(1) The center (h,k) is the midpoint of both the transverse axis and the conjugate axis
\n" ); document.write( "(2) The length of the transverse axis is 2a; the length of the conjugate axis is 2b

\n" ); document.write( "You now have all the pieces you need to write the equation.

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