document.write( "Question 111994: Hello, I am working on a word problem that I need some assistance on.
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document.write( "Here it is: A bus leaves a station at 1pm, traveling west at an average rate of 44m/h. One hour later a second bus leaves the same station at, traveling east at a rate of 48m/h. At what time will the two buses be 274 miles apart?\r
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document.write( "Now what I have been trying to do is take the rate of 44m/h and 48m/h and divide that into 274. I have come close to 7pm for the time at which the two buses will be 274 mi. apart. Is this the correct way of solving this problem or am I off base here? I appreciate your help here.\r
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document.write( "Thank You, Barb Neely \n" );
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Algebra.Com's Answer #81720 by BrittanyM(80)![]() ![]() ![]() You can put this solution on YOUR website! The fisrt bus left at 1:00PM going at 44mph. The total distance that we are looking for is 274m. We need to subtract the 44M forom the total of 274M since the second bus doesn't start until an hour later. So now, our total distance is 230M.\r \n" ); document.write( "\n" ); document.write( "274M - 44M = 230M\r \n" ); document.write( "\n" ); document.write( "Now, we can find the combined rate at which the busses are separating.\r \n" ); document.write( "\n" ); document.write( "44mph + 48mph = 92mph\r \n" ); document.write( "\n" ); document.write( "We can plug are known variables into the distance formula to find T, time.\r \n" ); document.write( "\n" ); document.write( "D = RT\r \n" ); document.write( "\n" ); document.write( "230M = 92mphT\r \n" ); document.write( "\n" ); document.write( "T = 2.5 \r \n" ); document.write( "\n" ); document.write( "Two and a half hours plus two o'clock (the time that the second bus started) gives us a time of 4:30PM. \n" ); document.write( " |