document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186303>Question 1186303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of the garden should be 2 less than 3 times the width. The area should be 16 cm. Find the dimensions & perimeter of the garden.​ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817192 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "x = width<BR>\n" );
document.write( "3x-2=length<br><BR>\n" );
document.write( "The area (length times width) is 16:<br><BR>\n" );
document.write( "x(3x-2)=16<BR>\n" );
document.write( "3x^2-2x=16<BR>\n" );
document.write( "3x^2-2x-16=0<BR>\n" );
document.write( "(3x-8)(x+2)=0<br><BR>\n" );
document.write( "x=8/3 or x=-2<br><BR>\n" );
document.write( "Reject the negative solution, since it makes no sense for the actual problem.<br><BR>\n" );
document.write( "ANSWERS:<BR>\n" );
document.write( "width = x = 8/3<BR>\n" );
document.write( "length = 3x-2 = 8-2=6<BR>\n" );
document.write( "area = (8/3)(6) = 16<BR>\n" );
document.write( "perimeter = twice width plus twice length = 2(8/3)+2(6) = 16/3+12 = 52/3 or 17 1/3<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );