document.write( "Question 1186254: Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7),
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Algebra.Com's Answer #817184 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Since the conjugate axis is mentioned, it is about hyperbola.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Its center is the point (7,1).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It has horizontal major axis y = 1, parallel to x-axis.\r\n" ); document.write( "\r\n" ); document.write( "The distance between vertices is 15 - (-1) = 16; hence, the major semi-axis length \"a\" is 16/2 = 8 units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It has vertical conjugate axis x = 7, parallel to y-axis.\r\n" ); document.write( "\r\n" ); document.write( "The length of the conjugate axis is 7 - (-5) = 12; hence, the minor semi-axis length \"b\" is 12/2 = 6 units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Combining all this info, the standard equation of the hyperbola is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |