document.write( "Question 1186254: Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7),
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Algebra.Com's Answer #817183 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Vertices: (\"15\", \"1\"), (\"-1\", \"1\"); \r
\n" ); document.write( "\n" ); document.write( "Endpoints of Conjugate Axis: (\"7\", \"7\"), (\"7\", \"-5\") \r
\n" ); document.write( "\n" ); document.write( "-> the center is at midpoint (\"%287%2B7%29%2F2\", \"%287-5%29%2F2\")=> C (\"7\",\"+1\") \r
\n" ); document.write( "\n" ); document.write( "the length of Conjugate Axis is \"2b=12\"=>\"b=6\"\r
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\n" ); document.write( "\n" ); document.write( "equation of hyperbola\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"........plug in known\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-7%29%5E2%2Fa%5E2-%28y-1%29%5E2%2F6%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-7%29%5E2%2Fa%5E2-%28y-1%29%5E2%2F36=1\"........use vertices (\"-1\", \"1\") to calculate \"a%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-1-7%29%5E2%2Fa%5E2-%281-1%29%5E2%2F36=1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-8%29%5E2%2Fa%5E2-%280%29%5E2%2F36=1\"\r
\n" ); document.write( "\n" ); document.write( "\"64%2Fa%5E2+=1\"\r
\n" ); document.write( "\n" ); document.write( "\"64=a%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "so, your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-7%29%5E2%2F64-%28y-1%29%5E2%2F36=1\"\r
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