document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186255>Question 1186255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the quadratic formula to solve 2x^6 - 3x^3 - 8 = 0. Write your answer correct to 3 significant figures.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817175 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it will be x^3=(1/2a)(-b+/- sqrt (b^2-4ac)<BR>\n" );
document.write( "think of this as let z=x^3. so the equation becomes 2z^2-3z-8=0<BR>\n" );
document.write( "=(1/4)(3+/- sqrt(9+64))<BR>\n" );
document.write( "=(1.4)(3+/- sqrt(73)<BR>\n" );
document.write( "=2.89, -1.39<BR>\n" );
document.write( "the answer is the cube root of each of those, since we solved for x^3/z<BR>\n" );
document.write( "x=-1.11, 1.42\r<BR>\n" );
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