Algebra.Com's Answer #817138 by ikleyn(53751)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "Solve  +  = 16.
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document.write( " @MathLover1 solved ANOTHER equation, DIFFERENT from the given in the post.\r
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document.write( " So her solution and her answer have no any relation to the posed problem.\r
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document.write( " I came to bring the correct solution.\r
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document.write( "Your starting equation is\r\n" );
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document.write( " + = 16.\r\n" );
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document.write( "Introduce new variable y =  . Then the given equation takes the form\r\n" );
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document.write( " 3y +  = 16.\r\n" );
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document.write( "Multiply both sides by y. You will get an EQUIVALENT equation\r\n" );
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document.write( " 3y^2 + 5 = 16y, \r\n" );
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document.write( "or\r\n" );
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document.write( " 3y^2 - 16y + 5 = 0.\r\n" );
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document.write( "Apply the quadratic formula and find the roots. They are y = 5 and y =  .\r\n" );
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document.write( "Hence, for x =  , we have two values  = 25 and  =  .\r\n" );
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document.write( "ANSWER. The given equation has two solutions x= 25 and/or x= .\r\n" );
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document.write( "You can easily check it by substituting these found values of x into the original equation.\r\n" );
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document.write( "Solved.\r
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