document.write( "Question 1186103: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist? \n" ); document.write( "
Algebra.Com's Answer #817116 by MathTherapy(10551)\"\" \"About 
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\n" ); document.write( "Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist?
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Let rate of slower cyclist be S
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document.write( "Then rate of faster cyclist = S + 5
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document.write( "We then get the following DISTANCE equation: 5S + 5(S + 5) = 155
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document.write( "S + S + 5 = 31 ------ Factoring out GCF, 5/Dividing by 5
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document.write( "2S = 26
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document.write( "Speed of slower cyclist, or \"highlight_green%28matrix%281%2C6%2C+S%2C+%22=%22%2C+26%2F2%2C+%22=%22%2C+13%2C+mph%29%29\"
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document.write( "You should now be able to find the faster cyclist's rate/speed. \n" );
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