document.write( "Question 112004: Find two consecutive odd integers such that 5 times the first integer is 12 more then 3 times the second \n" ); document.write( "
Algebra.Com's Answer #81711 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let u=first #, w=second #\r
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\n" ); document.write( "\n" ); document.write( "Remember, consecutive odd integers follow the form \"2x%2B1\", \"2x%2B3\", etc. \r
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\n" ); document.write( "\n" ); document.write( "So the statement \"5 times the first integer is 12 more then 3 times the second\" translates to\r
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\n" ); document.write( "\n" ); document.write( "\"5u=3w%2B12\" \r
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\n" ); document.write( "\n" ); document.write( "\"5%282x%2B1%29=3%282x%2B3%29%2B12\" Let \"u=2x%2B1\" and \"w=2x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"10x%2B5=6x%2B9%2B12\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"10x%2B5=6x%2B21\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"10x=6x%2B21-5\"Subtract 5 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"10x-6x=21-5\" Subtract 6x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"4x=21-5\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"4x=16\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2816%29%2F%284%29\" Divide both sides by 4 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=4\"\r
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\n" ); document.write( "\n" ); document.write( "Now plug in \"x=4\" into \"2x%2B1\" to get \r
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\n" ); document.write( "\n" ); document.write( "\"2%284%29%2B1=8%2B1=9\"\r
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\n" ); document.write( "\n" ); document.write( "So our first number is 9\r
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\n" ); document.write( "\n" ); document.write( "Now plug in \"x=4\" into \"2x%2B3\" to get \r
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\n" ); document.write( "\n" ); document.write( "\"2%284%29%2B3=8%2B3=11\"\r
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\n" ); document.write( "\n" ); document.write( "So our second number is 11\r
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\n" ); document.write( "\n" ); document.write( "\"5u=3w%2B12\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"5%2A9=3%2A11%2B12\" Plug in the given numbers\r
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\n" ); document.write( "\n" ); document.write( "\"45=33%2B12\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"45=45\" Add. So these numbers work.
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