document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186189>Question 1186189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line m is the perpendicular bisector of both AB and CD. Which of the following must be true and why (or why not)?<BR>\n" );
document.write( "AC=BD<BR>\n" );
document.write( "(I know it is true and I have proved AC=BD when A and C are both on one side, but there is also a possibility with different triangles, where C is on the opposite side of A. How do I prove that? Thank you.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817109 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The figure is a trapezoid in which line m is perpendicular to both bases and bisects both of them.<br><BR>\n" );
document.write( "The proofs for the two cases should be nearly identical.  In both cases, AC is the hypotenuse of a right triangle; one leg is along the longer base of the trapezoid and the length of the other leg is the distance between the two bases of the trapezoid.<br><BR>\n" );
document.write( "In one case the length of the base of the triangle is half the longer base minus half the shorter base; in the other case it is half the longer base plus half the shorter base.<br><BR>\n" );
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