document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186076>Question 1186076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The volume of water Vm^3, is directly proportional to the square  of its cross-sectional radius, R m. If the radius of the pipe is increased by 150%, find the percentage increase of the volume.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817063 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The problem says the volume of water (in the pipe), V, is proportional to the square of the cross-sectional radius, r.  That means we are talking about a pipe of fixed length.  So when the radius is increased, the length remains the same.<br><BR>\n" );
document.write( "If the radius r of the pipe is INCREASED BY 150%, then the new radius is r plus 150% of r, which is 2.5r.<br><BR>\n" );
document.write( "Then, since the volume is proportional to the square of the radius, the volume is increased by a factor of (2.5)^2 = 6.25.<br><BR>\n" );
document.write( "And that means the percent INCREASE in the volume is 525%.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );