document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186113>Question 1186113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line parallel to 3x + 4y= 20 and at a distance 5 from this line </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #817036 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=817036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the line parallel to 3x + 4y = 20 be given by  3x + 4y = C, for some constant C.\r<BR>\n" );
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document.write( "Then the distance between the two lines is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=abs%28C-20%29%2Fsqrt%283%5E2+%2B+4%5E2%29+=+5 ALIGN=MIDDLE  ALT=\"abs%28C-20%29%2Fsqrt%283%5E2+%2B+4%5E2%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or equivalently, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=abs%28C-20%29+=+25 ALIGN=MIDDLE  ALT=\"abs%28C-20%29+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Solving this absolute-value equation leads to C - 20 = 25 or C - 20 = -25.\r<BR>\n" );
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document.write( "===> C  = 45 or C = -5.\r<BR>\n" );
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document.write( "Thus there are two lines which satisfy the given conditions, namely 3x + 4y = 45   and 3x + 4y = -5. </SPAN>\n" );
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