document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1186092>Question 1186092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. and Mrs. Austria love to run around the town. From past experiences, they know that<BR>\n" );
document.write( "Mr. Austria can run 6km in the time it takes Mrs. Austria to run 4km. They have decided<BR>\n" );
document.write( "that they need to run the same distance, 9km, and finish together. How much of a head<BR>\n" );
document.write( "start does Mrs. Austria need for them to finish together </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816970 by </B><A HREF=/tutors/aboutme.mpl?userid=JBnovelwriter><B>JBnovelwriter(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBnovelwriter><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBnovelwriter><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4/4=1km<BR>\n" );
document.write( "6/4=1.5km per 1km of his (he is .5km faster to go the same 1km as her or basically she goes 2/3's his speed) <BR>\n" );
document.write( "9 total km / 1.5 km= 6<BR>\n" );
document.write( "9-6=3<BR>\n" );
document.write( "so he needs to give her a 3km head start\r<BR>\n" );
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document.write( "so for every 2km she runs he is on the 3rd km<BR>\n" );
document.write( "so when she is at 4km he's at 6km<BR>\n" );
document.write( "so when she is at 6km he's at 9km<BR>\n" );
document.write( "that's a 3km gap which is why he needs to give her a 3km head start.<BR>\n" );
document.write( " </SPAN>\n" );
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