document.write( "Question 1186062: The figure shows an isosceles triangle with equal sides of
\n" ); document.write( "length \"a\" surmounted by a semicircle. What should the measure of angle θ be in order to maximize the total area? \r
\n" ); document.write( "\n" ); document.write( "https://imgur.com/a/tyyqfL4
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Algebra.Com's Answer #816956 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "\n" ); document.write( "Refer to the figure above, where we've sliced the original picture down the middle. Here \"alpha+=+theta%2F2+\". If we maximize this figure in terms of \"alpha\", we just need to double that to find \"theta\".\r
\n" ); document.write( "\n" ); document.write( "\"A%5Barc%5D\" = \"+%281%2F4%29%2Api%2Ar%5E2+\"
\n" ); document.write( "\"A%5Btriangle%5D\" = \"+%281%2F2%29r%2Ah+\"\r
\n" ); document.write( "\n" ); document.write( "Observe:
\n" ); document.write( "\"+r+=+a%2Asin%28alpha%29+\"
\n" ); document.write( "\"+h+=+a%2Acos%28alpha%29+\"\r
\n" ); document.write( "\n" ); document.write( "Substituting for r and h:
\n" ); document.write( "\"A%5Barc%5D\" = \"+%281%2F4%29%2Api%2Aa%2Asin%5E2%28alpha%29+\"
\n" ); document.write( "\"A%5Btriangle%5D\" = \"+%281%2F2%29%28a%2Asin%28alpha%29%29%2A%28a%2Acos%28alpha%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+A%5Btotal%5D+\" = \"A%5Barc%5D+%2B+A%5Btriangle%5D+\"
\n" ); document.write( "= \"+%281%2F4%29pi%2Aa%5E2%2Asin%5E2%28alpha%29+\" + \"+%281%2F2%29%28a%2Asin%28alpha%29%29%2A%28a%2Acos%28alpha%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "...factoring out \"+%281%2F4%29a%5E2%2Asin%28alpha%29+\"
\n" ); document.write( "= (*)\r
\n" ); document.write( "\n" ); document.write( "Now take the derivative of \"A%5Btotal%5D\" with respect to \"+alpha+\":\r
\n" ); document.write( "\n" ); document.write( "\"+dA%5Btotal%5D+%2Fd%5Balpha%5D+\" =
\n" ); document.write( "
\n" ); document.write( "= \"+%281%2F4%29a%5E2%2A%28pi%2Asin%282%2Aalpha%29%2B2cos%282%2Aalpha%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "... substitute \"theta+=+2%2Aalpha+\" ...
\n" ); document.write( "= \"+%281%2F4%29a%5E2%28pi%2Asin%28theta%29%2B2cos%28theta%29%29+\" \r
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\n" ); document.write( "\n" ); document.write( "This last function is zero at approx. \"theta+\" = 2.575rad, \"theta\"= 5.716rad, ...\r
\n" ); document.write( "\n" ); document.write( "By graphing, one can see 2.575rad results in a maximum area, while 5.716 results in a minimal area. \r
\n" ); document.write( "\n" ); document.write( "2.575rad is approx 147.54degrees.\r
\n" ); document.write( "\n" ); document.write( "Ans: \"theta\" = \"147.54%5Eo\" maximizes the total area.\r
\n" ); document.write( "\n" ); document.write( "Just in case...
\n" ); document.write( "If you were interested in the value of the total maximal area, note that you would need a modified form of (*) because that equation computes 1/2 of the total area:
\n" ); document.write( " \"+A%5Btotal%5D+\" = \n" ); document.write( "
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