document.write( "Question 1186035: The results of the latest writing of the LSAT (Law School Aptitude Test) showed results that were normally distributed with a mean score of 829 and a standard deviation of 50.\r
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document.write( "The Osgoode Hall Law School wants candidates for admission to be in the top 1
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document.write( " of LSAT test scores. What is the minimum test score a candidate needs to achieve to be considered for admission to this school? \r
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document.write( "If a group of 42 applicants is randomly selected, what is the probability that the group average is not less than 849? \n" );
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Algebra.Com's Answer #816953 by Theo(13342)![]() ![]() You can put this solution on YOUR website! men of the population is 829 \n" ); document.write( "standard deviation of the population is 50.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "critical z-score for admission to be in the top 1 percent is equal to 2.326348 rounded to 6 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x - m) / s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score \n" ); document.write( "x is the individual score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the critical z-score formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2.326348 = (x - 829) / 50.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 2.326348 * 50 + 829 = 945.3174.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sample size = 42.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when you're dealing with the mean of a sample, rather than an individual score, you need to use the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard error = standard deviation / square root of sample size = 50 / sqrt(42) = 7.715167 rounded to 6 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x - m) / s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score \n" ); document.write( "x is the sample mean \n" ); document.write( "m is the population mean \n" ); document.write( "s is the standard error\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (849 - 829) / 7.715167 = 2.5923 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area to the right of that z-score is equal to .00477 rounded to 5 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the probability that the group average is not less than 849.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i used the following calculator to confirm these results are accurate, assuming i calculated the standard error correctly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.statskingdom.com/normal.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the results from the use of that calculator are shown below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "minimum score for top 1%:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of sample mean not less than 849.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |