document.write( "Question 1186024: Please can you help me
\n" ); document.write( "Find the values of a and b if ax^4+bx^3-8x^2+6x-6 has a remainder of 2x+1 when divided by x^2-1 \n" ); document.write( "
Algebra.Com's Answer #816927 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Here's another way to do it, by dividing directly with long division:\r\n" );
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document.write( "                    ax2+       bx+    (-8+a)\r\n" );
document.write( "x2+0x-1)ax4+bx3-     8x2+      6x-         6\r\n" );
document.write( "        ax4+0x3-     ax2\r\n" );
document.write( "            bx3+(-8+a)x2+      6x\r\n" );
document.write( "            bx3+     0x2-      bx\r\n" );
document.write( "                (-8+a)x2+  (6+b)x-         6\r\n" );
document.write( "                (-8+a)x2+      0x-    (-8+a)\r\n" );
document.write( "                           (6+b)x+(-6+(-8+a))\r\n" );
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document.write( "For this remainder to be 2x+1,\r\n" );
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document.write( "6+b = 2        -6+(-8+a) = 1\r\n" );
document.write( "  b = -4          -6-8+a = 1\r\n" );
document.write( "                   -14+a = 1\r\n" );
document.write( "                       a = 15\r\n" );
document.write( "                       \r\n" );
document.write( "Edwin
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