document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16748>Question 16748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution to \r<BR>\n" );
document.write( "\n" );
document.write( "((cuberoot 2) raised to the 2 -x) = 2 raised to the x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8169 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ((cuberoot 2) raised to the 2 -x) = 2 raised to the x^2<BR>\n" );
document.write( "  note that cube root of x = x^(1/3)...OR IN GENERAL..(x)^(1/p) is called pth. root of x .using this property we get ..<BR>\n" );
document.write( "  [(2)^(1/3)]^(2-x) = (2)^(x^2)<BR>\n" );
document.write( "  [(2)^{(2-x)/3}] = (2)^(x^2)..bases being same (2) in this equation,powers should be equal . hence <BR>\n" );
document.write( "  (2-x)/3 = x^2<BR>\n" );
document.write( "   2-x = 3x^2<BR>\n" );
document.write( "  3x^2 + x - 2 = 0<BR>\n" );
document.write( " 3x^2 +3x - 2x-2 = 0<BR>\n" );
document.write( "3x(x+1)-2(x+1) = 0 <BR>\n" );
document.write( "(x+1)(3x-2)=0<BR>\n" );
document.write( " x=-1 or x=2/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );