document.write( "Question 1185996: The length of a rectangle is 5 cm more than 3 times its width. The area of the rectangle is 1428 square cm. Find the length and width of the rectangle.\r
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Algebra.Com's Answer #816864 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is \"5\" cm more than \"3\" times its width:\r
\n" ); document.write( "\n" ); document.write( "\"L=3W%2B5\".......eq.1\r
\n" ); document.write( "\n" ); document.write( " The area of the rectangle is \"1428\" square cm.\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"1428=L%2AW\"........substitute \"L\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"1428=%283W%2B5%29%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"1428=3W%5E2%2B5W\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2%2B5W-1428=0\"....factor\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-63W%2B68W-1428=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283W%5E2-63W+%29%2B%2868W-1428%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%28W-21+%29%2B68%28W-21%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28W+-+21%29+%283W+%2B+68%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "=> \"%28W+-+21%29+++=+0\" =>\"W+=+21cm\"\r
\n" ); document.write( "\n" ); document.write( "go to \"L=3W%2B5\".......eq.1, substitute \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"L=3%2A21%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"L=68cm\"\r
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