document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111973>Question 111973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coins does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81686 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coins does she have?<BR>\n" );
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document.write( "Let number of nickels be \"x\" ; value of these is 5x cents<BR>\n" );
document.write( "# of dimes is \"50-x\" ; value of these is 10(50-x)= 500-10x cents<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "value + value = 350 cents<BR>\n" );
document.write( "5x + 500-10x = 350<BR>\n" );
document.write( "-5x = -150<BR>\n" );
document.write( "x = 30 ( # of nickels)<BR>\n" );
document.write( "50-x=20( # of dimes)<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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