document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185988>Question 1185988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following:\r<BR>\n" );
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document.write( "(a) the mean and z=0\r<BR>\n" );
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document.write( "(b) the mean and z =1.96\r<BR>\n" );
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document.write( "(c) z= -1.50 and z= -1.50\r<BR>\n" );
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document.write( "(d) z= -.30 and z= -.10\r<BR>\n" );
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document.write( "(e) z= 1.00 and z= 2.00 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816857 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i used the following table.\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF= \"https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf\" target = \"_blank\">https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf</a>\r<BR>\n" );
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document.write( "in a normal distribution z-score table, the mean is at z = 0 and the standard deviation is equal to 1.\r<BR>\n" );
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document.write( "z-score               area to the left of\r\n" );
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document.write( "the mean                    .5\r\n" );
document.write( "0                           .5\r\n" );
document.write( "1.96                        .97500\r\n" );
document.write( "-1.5                        .06681\r\n" );
document.write( "-.5                         .30854\r\n" );
document.write( "-.3                         .38209\r\n" );
document.write( "-.1                         .46017    \r\n" );
document.write( "1                           .84134\r\n" );
document.write( "2                           .97725   \r\n" );
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document.write( "</PRE>\r<BR>\n" );
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document.write( "when you want the area between, you subtract the smaller area from the larger area.<BR>\n" );
document.write( "that's the area between.\r<BR>\n" );
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document.write( "answers to your questions are below:\r<BR>\n" );
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document.write( "Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following:<BR>\n" );
document.write( "(a) the mean and z = 0 equals .5 minus .5 = 0.<BR>\n" );
document.write( "(b) the mean and z = 1.96 equals .97500 minus .5 = .47500.<BR>\n" );
document.write( "(c) z= -1.50 and z= -1.50 equals .06681 minus .06681 = 0.<BR>\n" );
document.write( "(d) z= -.30 and z= -.10 equals .46017 minus .38209 = .07808<BR>\n" );
document.write( "(e) z= 1.00 and z= 2.00 equals .97725 minus .84134 = .13591\r<BR>\n" );
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document.write( "      </SPAN>\n" );
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