document.write( "Question 1185961: Expand (1/2-2x)^5 up to the term in x^3. If the coefficient of x^2 in the expansion of (1+ax+3x^2)(1/2-2x)^5 is 13/2, find the coefficient of x^3. \n" ); document.write( "
Algebra.Com's Answer #816828 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) Expand (1/2-2x)^5 up to the term in x^3 \n" ); document.write( " \n" ); document.write( "ANSWER: \n" ); document.write( "(2) Find a, given that the coefficient of x^2 in \n" ); document.write( " \n" ); document.write( "The contributions to the x^2 coefficient come from the constant term in the first polynomial times the coefficient of x^2 in the second, the coefficient of the x term in the first polynomial times the coefficient of the x term in the second, and the coefficient of the x^2 term in the first polynomial times the constant term in the second: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: a=-9/4 \n" ); document.write( "(3) Find the coefficient of x^3 in (1+ax+3x^2)(1/2-2x)^5 \n" ); document.write( "The contributions to the x^3 coefficient come from the constant term in the first polynomial times the coefficient of the x^3 term in the second, the coefficient of the x term in the first polynomial times the coefficient of the x^2 term in the second, and the coefficient of the x^2 term in the first polynomial times the coefficient of the x term in the second: \n" ); document.write( " \n" ); document.write( "ANSWER: -265/8 \n" ); document.write( "The answers are confirmed with this completely expanded polynomial as calculated on wolframalpha.com: \n" ); document.write( "1/32 - (89 x)/128 + (13 x^2)/2 - (265 x^3)/8 + 100 x^4 - 182 x^5 + 192 x^6 - 96 x^7 \n" ); document.write( " \n" ); document.write( " |