document.write( "Question 1185901: a watch which gains 5 seconds every hour was set to read correct time at 0300
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document.write( "hours monday determine the time in 12hours system the watch will show on Tuesday
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document.write( "at 0900 hour the same week. \n" );
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Algebra.Com's Answer #816777 by Edwin McCravy(20062) You can put this solution on YOUR website! a watch which gains 5 seconds every hour was set to read correct time at 0300 \n" ); document.write( "hours monday determine the time in 12hours system the watch will show on Tuesday \n" ); document.write( "at 0900 hour the same week \n" ); document.write( " \r\n" ); document.write( "That's 30 hours, so it has gained 150 seconds which is 2 1/2 minutes, so it'll\r\n" ); document.write( "read 9:02 1/2 A.M. at 9:00 A.M\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |